document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309005>Question 309005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> chuck and dana agree to meet in chicago for the weekend. Chuck travels 148 miles in the same time that dana travels 124 mile. If Chuck;s rate of travel is 6mph more than Dana's then at what rate does chuck travels.? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220952 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let Dana's rate of travel be xmph<BR>\n" );
document.write( "Chuck travels at a rate of x+6 mph<BR>\n" );
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document.write( "Time taken by Dana to travel 124 miles = 124/x<BR>\n" );
document.write( "Time taken by chuck in the same time = 148/x+6\r<BR>\n" );
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document.write( "124/x = 148/x+6\r<BR>\n" );
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document.write( "124(x+6)=148x<BR>\n" );
document.write( "124x + 744=148x\r<BR>\n" );
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document.write( "148x-124x= 744<BR>\n" );
document.write( "24x= 744\r<BR>\n" );
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document.write( "x=31 which is dan'a rate of travel<BR>\n" );
document.write( "chuck travels 31 +6 = 37 mph\r<BR>\n" );
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