document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309023>Question 309023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. the measure of the larger angle is 10 degrees more than three times the measures of the smaller angle. find the measures of these two angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220949 by </B><A HREF=/tutors/aboutme.mpl?userid=mollukutti><B>mollukutti(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mollukutti><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mollukutti><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Basic facts:\r<BR>\n" );
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document.write( "1. Two angles are said to be complimentary to each other when they add up to 90 degrees\r<BR>\n" );
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document.write( "Let us consider the smaller angle as x degrees<BR>\n" );
document.write( "Therefore the larger angle will be (x + 10) degrees\r<BR>\n" );
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document.write( "As the angles are complimentary they add upto 90 degrees. Hence the equation can be written as:\r<BR>\n" );
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document.write( "x + (x+10) = 90<BR>\n" );
document.write( "or, x + x + 10 = 90<BR>\n" );
document.write( "or, 2x + 10 = 90<BR>\n" );
document.write( "or, 2x + 10 - 10 = 90 - 10   (subtracting 10 from both sides)<BR>\n" );
document.write( "or, 2x = 80<BR>\n" );
document.write( "or, 2x/2 = 80/2   (dividing both sides by 2)<BR>\n" );
document.write( "or, x = 40\r<BR>\n" );
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document.write( "Hence the smaller angle is 40 and the larger angle is (40 + 10) 50 degrees. </SPAN>\n" );
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