document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36006>Question 36006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor the quadratic expression completely, and find the roots of the expression.\r<BR>\n" );
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document.write( "49x^2 - 14x - 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22093 by </B><A HREF=/tutors/aboutme.mpl?userid=vidhyak><B>vidhyak(98)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vidhyak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution \r<BR>\n" );
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document.write( "ax^2-bx-c<BR>\n" );
document.write( "49x^2 - 14x - 3\r<BR>\n" );
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document.write( "Factorize the variable b (in our case -14) into 2 numbers (say b1,b2) so that b1* b2 = ac(49*-3) and b1+b2 = b\r<BR>\n" );
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document.write( "We can split the number -14 as -21, +7  so that (-21*7 = -147 which is equal = ac (49*-3))\r<BR>\n" );
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document.write( "and -21+7 = -14 which is b<BR>\n" );
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document.write( "49x^2 - 14x - 3<BR>\n" );
document.write( "49x^2 - 21x + 7x - 3<BR>\n" );
document.write( "7x(7x-3)+7x-3<BR>\n" );
document.write( "7x(7x-3)+1(7x-3)<BR>\n" );
document.write( "(7x+1)(7x-3)\r<BR>\n" );
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document.write( "Solving we get x= -1/7 and 3/7<BR>\n" );
document.write( "or -.1428 and 0.4285\r<BR>\n" );
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document.write( " </SPAN>\n" );
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