document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308957>Question 308957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One leg of a right triangle is 5 cm shorter than the other leg. The length of the hypotenuse is 25 cm. Find the length of the shorter leg.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220904 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one leg be x cm<BR>\n" );
document.write( "the other leg will be x-5 cm\r<BR>\n" );
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document.write( "hyptenuse = 25 cm\r<BR>\n" );
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document.write( "Using pytagorean theorem\r<BR>\n" );
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document.write( "x^2 +(x-5)^2= 25^2<BR>\n" );
document.write( "X^2 +x^2-10x+25= 625<BR>\n" );
document.write( "2x^2 -10x -600=0<BR>\n" );
document.write( "x^2-5x-300=0<BR>\n" );
document.write( "x^2-20x+15x-300=0<BR>\n" );
document.write( "x(x-20)+15(x-20)=0<BR>\n" );
document.write( "(x-20(x+15)=0\r<BR>\n" );
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document.write( "x=20 which is positive<BR>\n" );
document.write( "one leg is 20cm<BR>\n" );
document.write( "the other leg = 15 cm </SPAN>\n" );
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