document.write( "Question 308822: I was wondering what the pressure must be a mile deep in the water. \r
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document.write( "If water weighs 59.52 lbs/ft^3, what pressure in pounds per square inch would it cause at 5,280 feet below the surface? Hint: Calculate the weight of a column of water with an area of 1 square inch and 5,280 feet high.
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Algebra.Com's Answer #220801 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Calculate the volume of the 1 inch square x 1 mile column. \n" ); document.write( "Convert the 1 mile to feet since the density is in feet. \n" ); document.write( "Convert the 1 inch square to 1 ft square also. \n" ); document.write( "1 in*1 in*(1 ft/12 in)^2=1/144 ft^2 \n" ); document.write( "1 mile=5280 ft \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Find the weight of the column by multiplying the volume and the density of water. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That weight acts on the 1 inch square area. \n" ); document.write( " \n" ); document.write( " |