document.write( "Question 36048: Hi Could somebody help me or give me guidance on how to answer the questions below please, thanks, Sarah
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document.write( "Sam's Takeaway has the opportunity to open a new shop, but is unsure of the demand. Initial estimations are that there is a 80% chance of high demand and 20% chance of low demand.
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document.write( "Sam's Takeaway must choose between a large, medium or small shop. The large shop has the potential to make a profit of £50,000 if there is high demand but a loss of £10,000 if demand is low. The medium shop could make £40,000 or £15,000 depending on whether there is high or low demand, respectively. Whilst, the small shop could yield a £20,000 profit with high demand or £10,000 with low demand.\r
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document.write( "1 (a) Sam will use the Expect Value Approach, with the probabilities above. Construct a table, in Microsoft Excel to compare the decision alternatives. This table should use formulas where appropriate, and be able to clearly show the “expected value” and also a description of the preferred shop size.
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document.write( "(6 marks)\r
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document.write( " (b) Sam's Takeaway revises their estimations from 80% high demand and 20% low demand to 70% high demand and 30% low demand Does this change to decision alternative, and if so how? \n" );
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Algebra.Com's Answer #22080 by Prithwis(166)![]() ![]() ![]() You can put this solution on YOUR website! Find the probabilities of each event, as specified in your question. \n" ); document.write( "The probability of high demand for Sam to open a new shop is .80; \n" ); document.write( "The probability of low demand for Sam to open a new shop is .20; \n" ); document.write( "For Large Shop: \n" ); document.write( "Potential profit on high demand is £50,000 \n" ); document.write( "Potential loss on low demand is £10,000 \n" ); document.write( "Expected value is determined as E = x1.p1 + x2.p2 + ... + xn.pn where xi is the value associated with i-th event and pi is the probability of i-th event. \n" ); document.write( "E (for large shop) = (£50,000)(.8) + (-£10,000)(.2) (-ve value is due to loss) \n" ); document.write( "=> E (for large shop) = £40,000 - £2000 = £38,000 (expected gain); \n" ); document.write( "E (for medium shop) = (£40,000)(.8) + (£15,000)(.2) \n" ); document.write( "=> E (for medium shop) = £32,000 + £3000 = £35,000 (expected gain); \n" ); document.write( "E (for small shop) = (£20,000)(.8) + (£10,000)(.2) \n" ); document.write( "=> E (for small shop) = £16,000 + £2000 = £18,000 (expected gain); \n" ); document.write( "Preferred shop size would be large because it generates the maximum profit. \n" ); document.write( ".......... \n" ); document.write( "You can use the same approach for the revised demand (probabilities will be different based on the revision; one will .7, instead of .8; the other will be .3, instead of .2)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |