document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308811>Question 308811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to find the perpendicular line to 2x+3y=6\r<BR>\n" );
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document.write( "I know in order to find a perpendicular line you need to get the reciprocal but I'm not sure what I need to flip and turn into a negative. I tried writing it in y=mx+b form, but not really sure where to go from here. This is what I have so far.\r<BR>\n" );
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document.write( "2x+3y=6<BR>\n" );
document.write( "-2x  -2x<BR>\n" );
document.write( "________<BR>\n" );
document.write( "3y=-2x+6<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "3   3  3\r<BR>\n" );
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document.write( "y=-2x+2<BR>\n" );
document.write( "   -<BR>\n" );
document.write( "   3\r<BR>\n" );
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document.write( "Not really sure the best way to show that I divided by 3 and how to write the fraction <BR>\n" );
document.write( "-2x<BR>\n" );
document.write( "          -<BR>\n" );
document.write( "          3\r<BR>\n" );
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document.write( "So thats how I did it, hope it makes sense :)<BR>\n" );
document.write( "After playing around on a graph I found the answer is <BR>\n" );
document.write( "y=2x-2<BR>\n" );
document.write( "                                                        -<BR>\n" );
document.write( "                                                        3<BR>\n" );
document.write( "but I don't know how to get that! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220799 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Best way to show it is like this:<BR>\n" );
document.write( "3y=-2x+6<BR>\n" );
document.write( "y=(-2x+6)/3<BR>\n" );
document.write( "Because then there is no confusion.<BR>\n" );
document.write( "OK, so the slope of this line is,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m1=-2%2F3 ALIGN=MIDDLE  ALT=\"m1=-2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So then the negative reciprocal would be the slope of the perpendicular line.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m2=3%2F2 ALIGN=MIDDLE  ALT=\"m2=3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Use the slope-intercept form,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%283%2F2%29x%2Bb ALIGN=MIDDLE  ALT=\"y=%283%2F2%29x%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If you have a point that needs to be on the new line, you would then use it here to solve for b. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=y-%283%2F2%29x ALIGN=MIDDLE  ALT=\"b=y-%283%2F2%29x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Any b will yield a line that is perpendicular to the original line. <BR>\n" );
document.write( "Here's a graph when <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=0 ALIGN=MIDDLE  ALT=\"b=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+%28-2x%2B6%29%2F3%2C+%283%2F2%29x%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+%28-2x%2B6%29%2F3%2C+%283%2F2%29x%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );