document.write( "Question 308795: I used the formula (x-h)^2 +(y-k)^2=r^2 to determine the equation of the circle. I got c=(4,0)r=sqrt 13 (x-4)^2+(y-0)^2=(sqrt13)^2
\n" ); document.write( "(x-4)^2=(y-0)^2 =13 but now I have to determine where the circle intersects the x-axis using a system of equations. Can you please show me how to do this.
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Algebra.Com's Answer #220794 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
When you're on the x-axis, then y=0.
\n" ); document.write( "\"%28x-4%29%5E2%2B%28y-0%29%5E2+=13\"
\n" ); document.write( "\"%28x-4%29%5E2%2B%280-0%29%5E2+=13\"
\n" ); document.write( "\"%28x-4%29%5E2=13\"
\n" ); document.write( "I think you can take it from there to solve for the two x values.
\n" ); document.write( "Remember that then y=0 in the ordered pair.
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