document.write( "Question 308795: I used the formula (x-h)^2 +(y-k)^2=r^2 to determine the equation of the circle. I got c=(4,0)r=sqrt 13 (x-4)^2+(y-0)^2=(sqrt13)^2
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document.write( "(x-4)^2=(y-0)^2 =13 but now I have to determine where the circle intersects the x-axis using a system of equations. Can you please show me how to do this. \n" );
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Algebra.Com's Answer #220793 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (x-4)^2+(y-0)^2 =13 but now I have to determine where the circle intersects the x-axis using a system of equations. \n" ); document.write( "-------------------------- \n" ); document.write( "Let y = 0; then solve for \"x\": \n" ); document.write( "------------------------------------------------ \n" ); document.write( "(x-4)^2 = 13 \n" ); document.write( "--- \n" ); document.write( "x-4 = +-sqrt(13) \n" ); document.write( "--- \n" ); document.write( "x = 4+sqrt(13) or x = 4-sqrt(13) \n" ); document.write( "====================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |