document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308768>Question 308768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> john travels 45 miles in 2/3 of an hour. At this same rate, how far can he travel in 2 hours? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220777 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the formula d=vt, where d=distance, v=speed, and t=time\r<BR>\n" );
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document.write( "d=45 miles<BR>\n" );
document.write( "t=2/3 hr<BR>\n" );
document.write( "v= ?\r<BR>\n" );
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document.write( "v=d/t<BR>\n" );
document.write( "v=45/(2/3)<BR>\n" );
document.write( "v=45*3/2<BR>\n" );
document.write( "v=67.5 mph\r<BR>\n" );
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document.write( "Now use this rate, with t=2 hours to solve for a new distance:\r<BR>\n" );
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document.write( "d=vt<BR>\n" );
document.write( "d=(67.5)(2)<BR>\n" );
document.write( "d=135 miles\r<BR>\n" );
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document.write( "In two hours, John will travel 135 miles. </SPAN>\n" );
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