document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308702>Question 308702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log base 2 (3x+4)- log base 2 (x)= 1\r<BR>\n" );
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document.write( "do I turn this into a fraction? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220742 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use one of the logarithm laws. If you're subtracting a log of the same base, you can just turn it into a fraction with the same log base. I'll show you what I mean:\r<BR>\n" );
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document.write( "log base 2 (3x+4/x) = 1\r<BR>\n" );
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document.write( "Next, you need to use the definition of log, log base b (x) = y, where x=b^y.\r<BR>\n" );
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document.write( "Use this to convert to:\r<BR>\n" );
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document.write( "(3x+4)/x = 2^1<BR>\n" );
document.write( "(3x+4)/x = 2<BR>\n" );
document.write( "3x+4 = 2x<BR>\n" );
document.write( "x+4=0<BR>\n" );
document.write( "x=-4 </SPAN>\n" );
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