document.write( "Question 308590: a chemist has 6 liters of a 50% acid solution. how much water must be added to obtain a 20% acid solution? \n" ); document.write( "
Algebra.Com's Answer #220732 by ankor@dixie-net.com(22740)\"\" \"About 
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a chemist has 6 liters of a 50% acid solution.
\n" ); document.write( " how much water must be added to obtain a 20% acid solution?
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\n" ); document.write( "Let x = amt of water required
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\n" ); document.write( "A simple \"amt of acid\" equation
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\n" ); document.write( ".50(6) = .20(x+6)
\n" ); document.write( "3 = .2x + 1.2
\n" ); document.write( "3 - 1.2 = .2x
\n" ); document.write( "1.8 = .2x
\n" ); document.write( "x = \"1.8%2F.2\"
\n" ); document.write( "x = 9 liters of water required
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\n" ); document.write( "Check to see if the amt of acid remains the same (only the % changes)
\n" ); document.write( ".50(6) = .2(9+6)
\n" ); document.write( "3 = 3
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