document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308673>Question 308673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I am having a very difficult time figuring this statistics problem. I appreciate any help.\r<BR>\n" );
document.write( "\n" );
document.write( "A study of 47 golfers show that their average score on a particular course was 97. The standard deviation of the sample is 7. Find the 99% confidence interval of the mean score for all golfers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220720 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 99% confidence level means that you include 3 standard deviations from the mean.  In this case, the standard deviation is 7, and 3*7=21.  Now, from the mean of 97, both ADD and SUBTRACT 21:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "97-21=76<BR>\n" );
document.write( "97+21=118\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The interval is from 76 to 118.  In other words, 99% of the golfers scored between 76 and 118 on this golf course.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Dr. Robert J. Rapalje, Retired </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );