document.write( "Question 36047: Find the vertex and focus of y=x^2+6x+7 and sketch it's graph. \n" ); document.write( "
Algebra.Com's Answer #22068 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Find the vertex and focus of y=x^2+6x+7 and sketch it's graph. \n" ); document.write( "Y=X^2+2*X*3+3^2-3^2+7=(X+3)^2-2 \n" ); document.write( "Y+2=1(X+3)^2 \n" ); document.write( "COMPARING WITH STD.EQN.OF PARABOLA \n" ); document.write( "(X-H)^2=4A(Y-K)..WHOSE VERTEX IS (H,K)AND FOCUS IS (H,K+A) \n" ); document.write( "(X+3)^2=(Y+2) \n" ); document.write( "WE FIND H=-3...K=-2......A=1/4.......HENCE \n" ); document.write( "VERTEX IS (-3,-2) AND \n" ); document.write( "FOCUS IS (-3,-2+1/4)=(-3,-7/4) \n" ); document.write( "GRAPH IS \n" ); document.write( " |