document.write( "Question 36047: Find the vertex and focus of y=x^2+6x+7 and sketch it's graph. \n" ); document.write( "
Algebra.Com's Answer #22068 by venugopalramana(3286)\"\" \"About 
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Find the vertex and focus of y=x^2+6x+7 and sketch it's graph.
\n" ); document.write( "Y=X^2+2*X*3+3^2-3^2+7=(X+3)^2-2
\n" ); document.write( "Y+2=1(X+3)^2
\n" ); document.write( "COMPARING WITH STD.EQN.OF PARABOLA
\n" ); document.write( "(X-H)^2=4A(Y-K)..WHOSE VERTEX IS (H,K)AND FOCUS IS (H,K+A)
\n" ); document.write( "(X+3)^2=(Y+2)
\n" ); document.write( "WE FIND H=-3...K=-2......A=1/4.......HENCE
\n" ); document.write( "VERTEX IS (-3,-2) AND
\n" ); document.write( "FOCUS IS (-3,-2+1/4)=(-3,-7/4)
\n" ); document.write( "GRAPH IS
\n" ); document.write( " \"+graph%28+500%2C+500%2C+-10%2C+5%2C+-10%2C+50%2C+x%5E2%2B6x%2B7%29+\"
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