document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308586>Question 308586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the one's digit of a two digit number is one more than the ten's digit. If the digits of the number are reversed, the new number is 3 less than twice the original. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220668 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the one's digit of a two digit number is one more than the ten's digit. If the digits of the number are reversed, the new number is 3 less than twice the original. Find the number.\r<BR>\n" );
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document.write( "let the ten's digit be x<BR>\n" );
document.write( "the unit digit will be y\r<BR>\n" );
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document.write( "y=x+1<BR>\n" );
document.write( "y-x=1\r<BR>\n" );
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document.write( "10y+x= 2(10x+y)-3<BR>\n" );
document.write( "10y+x= 20x+2y-3<BR>\n" );
document.write( "8y-19x=-3<BR>\n" );
document.write( ".<BR>\n" );
document.write( "8y-8x -8y+19x= 8+3<BR>\n" );
document.write( "11x=11<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( "y=x+1<BR>\n" );
document.write( "y=2<BR>\n" );
document.write( "the number = 12 </SPAN>\n" );
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