document.write( "Question 308612: The hypotenuse of a right triangle is 8 feet less than three times the shorter leg and the longer leg is 8 feet more than twice the shorter leg. Find the lengths of the three sides of the triangle. \r
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Algebra.Com's Answer #220655 by mananth(16946)\"\" \"About 
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The hypotenuse of a right triangle is 8 feet less than three times the shorter leg and the longer leg is 8 feet more than twice the shorter leg. Find the lengths of the three sides of the triangle. \r
\n" ); document.write( "\n" ); document.write( "let the shorter leg be x
\n" ); document.write( "3times shorter leg = 3x
\n" ); document.write( "8 feet less than 3 times shorter leg = 3x-8
\n" ); document.write( "Hypotenuse = 3x-8
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\n" ); document.write( "2 times shorter leg = 2x
\n" ); document.write( "8 feet more than 2 times shorter leg
\n" ); document.write( "longer leg =2x+8
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\n" ); document.write( "x^2+(2x+8)^2= (3x-8)^2
\n" ); document.write( "x^2+4x^2+32x+64 = 9x^2-48x+64
\n" ); document.write( "4x^2-80x=0
\n" ); document.write( "4x(x-20)=0
\n" ); document.write( "x=20 feet\r
\n" ); document.write( "\n" ); document.write( "shorter leg = x
\n" ); document.write( "longer leg = 2x+8
\n" ); document.write( "=40+8
\n" ); document.write( "=48 feet
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\n" ); document.write( "hypotenuse = 3x-8
\n" ); document.write( "= 60-8
\n" ); document.write( "= 52 feet
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\n" ); document.write( "20^+48^2= 52^2
\n" ); document.write( "2704 = 2704\r
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