document.write( "Question 36054: Sara's river boat travels downstream 16 miles in 2 hours. It returns the same distance upstream in 3 hours. Find the rate of the boat in still water and the rate of the current. Please explain how to get the answer. Thank you \n" ); document.write( "
Algebra.Com's Answer #22065 by venugopalramana(3286) You can put this solution on YOUR website! SEE THIS WHICH IS SIMILAR TO YOUR PROBLEM AND SOLVE \n" ); document.write( "YOUR PROBLEM...NOTE THAT STILL WATER MEANS VELOCITY OF STREAM=0 \n" ); document.write( "A boat travels at the speed of 20 Miles per hour in \n" ); document.write( "still water. It travels 48 miles up stream, and then \n" ); document.write( "returns to the starting point in a total of five \n" ); document.write( "hours. The speed of the current is ____ miles per \n" ); document.write( "hour. \n" ); document.write( "distance =speed * time..or...time=distance/speed \n" ); document.write( "Still water speed of boat =20 mph \n" ); document.write( "let the stream velocity be =x mph \n" ); document.write( "so its speed upstream =20-x \n" ); document.write( "its speed down stream =20+x \n" ); document.write( "distance travelled either way =48 miles \n" ); document.write( "time taken to travel upstream=48/(20-x) \n" ); document.write( "time taken to travel down stream =48/(20+x) \n" ); document.write( "total time of travel =5 hours..hence \n" ); document.write( "[48/(20-x)]+[48/(20+x)]=5 \n" ); document.write( "48[(20+x+20-x)/((20-x)(20+x))]=5 \n" ); document.write( "48*40=5(20^2-x^2)=2000-5x^2 \n" ); document.write( "5x^2=2000-1920=8= \n" ); document.write( "x^2=80/5=16 \n" ); document.write( " |