document.write( "Question 36027This question is from textbook Algebra II
\n" ); document.write( ": Thank you for your help! \r
\n" ); document.write( "\n" ); document.write( "The distance an object falls from rest varies directly as the square of the time it has fallen. If the object fell 4 ft during the 1st half second, how far did it fall during the next 2 seconds? \r
\n" ); document.write( "\n" ); document.write( "I know the answer is 96ft but im not sure how to set it up. Thank you. \n" ); document.write( "
Algebra.Com's Answer #22058 by venugopalramana(3286)\"\" \"About 
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The distance an object falls from rest varies directly as the square of the time it has fallen.
\n" ); document.write( "THAT D = K*T^2...WHERE T IS TIME AND D IS DISTANCE FROM START OF FALL
\n" ); document.write( " If the object fell 4 ft during the 1st half second,
\n" ); document.write( "4=K*(1/2)^2=K/4
\n" ); document.write( "K=4*4=16
\n" ); document.write( "D=16T^2
\n" ); document.write( "how far did it fall during the next 2 seconds?
\n" ); document.write( "THAT IS TOTAL TIME OF 2+1/2=5/2 SEC.
\n" ); document.write( "D=16*(5/2)^2=16*5*5/(2*2)=100 FT.
\n" ); document.write( "BUT IT FLL 4 FT IN THE FIRST 1/2 SEC.
\n" ); document.write( "HENCE IT FELL 100-4=96 FT DURING NEXT 2 SECS.\r
\n" ); document.write( "\n" ); document.write( "I know the answer is 96ft but im not sure how to set it up. Thank you. \n" ); document.write( "
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