document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308450>Question 308450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Paul is 12. His father is 33. How many years ago was the father 4 times as old as the son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220550 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = number of years ago.\r<BR>\n" );
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document.write( "12-x = Paul's age x years ago<BR>\n" );
document.write( "33-x = His father's age x years ago.\r<BR>\n" );
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document.write( "33-x=4(12-x)\r<BR>\n" );
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document.write( "33-x=48-4x\r<BR>\n" );
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document.write( "Add 4x to each side:<BR>\n" );
document.write( "33-x+4x=48-4x+4x<BR>\n" );
document.write( "33+3x=48\r<BR>\n" );
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document.write( "Subtract 33 from each side<BR>\n" );
document.write( "3x=48-33<BR>\n" );
document.write( "3x-15<BR>\n" );
document.write( "x=5\r<BR>\n" );
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document.write( "Paul was 12-5=7<BR>\n" );
document.write( "Father was 33-5=28\r<BR>\n" );
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document.write( "It checks!!\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired </SPAN>\n" );
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