document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308441>Question 308441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to figure this one out and more importantly understand it in laymens terms. Let f(x)=x to the second power + [x] Evaluate f(2), f(-2) I used substitution but this does not seem right.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220516 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me to figure this one out and more importantly understand it in laymens terms. Let f(x)=x^2 + [x] <BR>\n" );
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document.write( "Evaluate f(2), f(-2) I used substitution but this does not seem right. <BR>\n" );
document.write( "f(2) = 2^2+2 = 4+2 = 6<BR>\n" );
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document.write( "f(-2) = (-2)^2+(-2) = 4-2 = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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