document.write( "Question 308413: I have a triangle, it is an isoceles (I think i spelled that wrong). I know it is isoceles because it has a base then, the two sides are marked congruent. I have the degree measure of one angle, its 70 degrees. So, i found out the other degree angles are 70, and 30. It gives me the base length, 10. I need to find the area. I know to find the area, I need to find the height. (A= 1/2 bh) That's where I got stuck. How do I do this problem? Thank you. \n" ); document.write( "
Algebra.Com's Answer #220496 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Couple of things. \n" ); document.write( "You did spell isoceles correctly. \n" ); document.write( "However your angle is off. \n" ); document.write( "The sum of the angles of a triange equal 180. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the angle is 40 degrees, not 30. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "If you drop a line from the 40 degree vertex that bisects the base you then create two right triangles from your isoceles triangle. \n" ); document.write( "From trig, you know that \n" ); document.write( " \n" ); document.write( "In your case, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "which is the height you need for the area equation. \n" ); document.write( "SO then, \n" ); document.write( " \n" ); document.write( "and the area is then, \n" ); document.write( " \n" ); document.write( "This is the area of the right triangle. \n" ); document.write( "Double it to get the area of the isoceles triangle. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |