document.write( "Question 308413: I have a triangle, it is an isoceles (I think i spelled that wrong). I know it is isoceles because it has a base then, the two sides are marked congruent. I have the degree measure of one angle, its 70 degrees. So, i found out the other degree angles are 70, and 30. It gives me the base length, 10. I need to find the area. I know to find the area, I need to find the height. (A= 1/2 bh) That's where I got stuck. How do I do this problem? Thank you. \n" ); document.write( "
Algebra.Com's Answer #220496 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Couple of things.
\n" ); document.write( "You did spell isoceles correctly.
\n" ); document.write( "However your angle is off.
\n" ); document.write( "The sum of the angles of a triange equal 180.
\n" ); document.write( "\"70%2B70%2BA=180\"
\n" ); document.write( "\"A=180-140\"
\n" ); document.write( "\"A=40\"
\n" ); document.write( "So the angle is 40 degrees, not 30.
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\n" ); document.write( "If you drop a line from the 40 degree vertex that bisects the base you then create two right triangles from your isoceles triangle.
\n" ); document.write( "From trig, you know that
\n" ); document.write( "\"tan%2870%29=OPP%2FADJ\"
\n" ); document.write( "In your case,
\n" ); document.write( "\"ADJ=%281%2F2%29%2810%29=5\"
\n" ); document.write( "\"OPP=h\"
\n" ); document.write( "which is the height you need for the area equation.
\n" ); document.write( "SO then,
\n" ); document.write( "\"h=5%2Atan%2870%29\"
\n" ); document.write( "and the area is then,
\n" ); document.write( "\"A=%281%2F2%29%285%29%2A5%2Atan%2870%29\"
\n" ); document.write( "This is the area of the right triangle.
\n" ); document.write( "Double it to get the area of the isoceles triangle.
\n" ); document.write( "\"Ai=2%281%2F2%2925%2Atan%2870%29\"
\n" ); document.write( "\"Ai=25%2Atan%2870%29\" or approximately
\n" ); document.write( "\"Ai=68.7\" sq. units.
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