document.write( "Question 308363: Consider the equation f(x)=x^2+6x+4
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document.write( "Find the x-intercepts by completing the square.
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document.write( "Find the vertex
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document.write( "Find the axis of symmetry\r
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document.write( "I tried working out this problem 3 times and i can not solve it. My teacher said that when i find the x-intercepts that i should leave my answer in square roots rather than the decimal approximations. \n" );
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Algebra.Com's Answer #220479 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! \"Consider the equation f(x)=x^2+6x+4 \n" ); document.write( "Find the x-intercepts by completing the square. \n" ); document.write( "Find the vertex \n" ); document.write( "Find the axis of symmetry \n" ); document.write( "I tried working out this problem 3 times and i can not solve it. My teacher said that when i find the x-intercepts that i should leave my answer in square roots rather than the decimal approximations.\"\r \n" ); document.write( "\n" ); document.write( "f(x) = x^2 + 6x + 4 \n" ); document.write( "set f(x) = 0 and complete the square \n" ); document.write( "coefficient of 6x is 6, half of 6 is 3, and 3 squared is 9, \n" ); document.write( "and 9 - 5 = 4 \n" ); document.write( "0 = (x + 3)^2 - 5 \n" ); document.write( "5 = (x + 3)^2 \n" ); document.write( "sqrt(5) = x + 3 OR -sqrt(5) = x + 3 \n" ); document.write( "-3 + sqrt(5) = x OR -3 - sqrt(5) = x (these are your x-intercepts) \n" ); document.write( "parabolic equation is in the form f(x) = a(x - h)^2 + k, where (h,k) are the coordinates of the vertex \n" ); document.write( "a = 1 and is positive so parabola opens upward \n" ); document.write( "h = -3 and k = - 5 so vertex is at (-3, -5) \n" ); document.write( "and axis of symmetry is x = h or x = -3 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |