document.write( "Question 308363: Consider the equation f(x)=x^2+6x+4
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document.write( "Find the x-intercepts by completing the square.
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document.write( "Find the vertex
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document.write( "Find the axis of symmetry\r
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document.write( "I tried working out this problem 3 times and i can not solve it. My teacher said that when i find the x-intercepts that i should leave my answer in square roots rather than the decimal approximations. \n" );
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Algebra.Com's Answer #220475 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! x-intercepts are when f(x)=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = x^2 + 6x + 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c term should be 9 for a perfect square (half of the b coefficient, squared)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "adding 5 ___ 5 = x^2 + 6x + 9 = (x + 3)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "taking square root ___ ±√5 = x + 3 ___ -3±√5 = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "axis of symmetry ___ x = -b / (2a) ___ x = -3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "vertex is on the axis of symmetry ___ f(-3) = (-3)^2 + 6(-3) + 4 = -5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "vertex ___ (-3, -5) \n" ); document.write( " |