document.write( "Question 308244: Two tanks on a training mission are 1,800 m apart on a straight road. The drivers find the angles of elevation to the helicopter hovering over the road between them to be 33° and 52°. Find the height of the helicopter to two significant digits. \n" ); document.write( "
Algebra.Com's Answer #220434 by mananth(16949)\"\" \"About 
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Two tanks on a training mission are 1,800 m apart on a straight road. The drivers find the angles of elevation to the helicopter hovering over the road between them to be 33° and 52°. Find the height of the helicopter to two significant digits.\r
\n" ); document.write( "\n" ); document.write( "Let point from where the angle observed as 33deg be A
\n" ); document.write( "Let point from where the angle observed as 52deg be B
\n" ); document.write( "The point of intersection of the vertical from the helicopter to the ground be C\r
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\n" ); document.write( "AB is given as 1800 meters
\n" ); document.write( "Let BC be x meters\r
\n" ); document.write( "\n" ); document.write( "ABC form a right triangle\r
\n" ); document.write( "\n" ); document.write( "Tan 33 = vertical height / x+1800\r
\n" ); document.write( "\n" ); document.write( "vertical height = tan33 * (x+1800)
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\n" ); document.write( "Tan 52 = vertical height / x
\n" ); document.write( "x*tan 52 = vertical height\r
\n" ); document.write( "\n" ); document.write( "So \r
\n" ); document.write( "\n" ); document.write( "xTan 52 = Tan 33* ( x+1800)
\n" ); document.write( "1.2799x = 0.6494(x+1800)
\n" ); document.write( "1.2799x= 0.6494x +1168.92
\n" ); document.write( "0.6305x= 1168.92
\n" ); document.write( "x= 1854 meters\r
\n" ); document.write( "\n" ); document.write( "1800+1854 = total distance from point A
\n" ); document.write( "=3654 meters\r
\n" ); document.write( "\n" ); document.write( "Tan 33= vertical height / 3654\r
\n" ); document.write( "\n" ); document.write( "vertical distance= 3654*tan33
\n" ); document.write( "= 2372.90 meters\r
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