document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308168>Question 308168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the function f(x)=e^(2x)+e^(x)-6 in the form of a quadratic equation by using the appropriate substitution, and solve for x.\r<BR>\n" );
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document.write( "I did not know how to do this problem, my teacher did not explain it well enough to me.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220384 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factoring ___ f(x) = (e^x + 3) (e^x - 2)\r<BR>\n" );
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document.write( "setting f(x) to zero to find roots ___ 0 = (e^x + 3) (e^x - 2)\r<BR>\n" );
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document.write( "e^x + 3 = 0 ___ e^x = -3 negative value is not realistic\r<BR>\n" );
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document.write( "e^x - 2 = 0 ___ e^x = 2 ___ x = ln(2) </SPAN>\n" );
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