document.write( "Question 308232: Find the area.\r
\n" ); document.write( "\n" ); document.write( "leg is 12
\n" ); document.write( "leg is x+4
\n" ); document.write( "hypotenuse is 2x \n" ); document.write( "
Algebra.Com's Answer #220381 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
one leg 12
\n" ); document.write( "another leg x+4\r
\n" ); document.write( "\n" ); document.write( "Hypotenuse = 2x\r
\n" ); document.write( "\n" ); document.write( "Area of a right triangle = = 1/2 * one leg * second leg\r
\n" ); document.write( "\n" ); document.write( "Area = 1/2 * 12*(x+4)\r
\n" ); document.write( "\n" ); document.write( "Area = 6x +24
\n" ); document.write( "..
\n" ); document.write( "..
\n" ); document.write( "(2x)^2= 12^2 + (x+4)^2
\n" ); document.write( "4x^2 = 144 +x^2 +8x+16\r
\n" ); document.write( "\n" ); document.write( "3x^2-8x-160=0
\n" ); document.write( "Use quadratic equation formula for roots x1,x2\r
\n" ); document.write( "\n" ); document.write( "x1= -(-8) + sqrt (-8)^2-4*3*(-160) / 2*3
\n" ); document.write( "x1= 8 + sqrt 64+1920 / 6
\n" ); document.write( "x1= 8.75
\n" ); document.write( "..
\n" ); document.write( "x2 =8 - sqrt 64+1920 / 6
\n" ); document.write( "x2= -6.09 ( this is not possible)\r
\n" ); document.write( "\n" ); document.write( "x= 8.75
\n" ); document.write( "Area= 6x+24
\n" ); document.write( "plug the value of x\r
\n" ); document.write( "\n" ); document.write( "6*8.75+24
\n" ); document.write( "= 76.5 square units\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );