document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308194>Question 308194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The directions are: <BR>\n" );
document.write( "Factor each polynomial, if possible. If the polynomial cannot be factored using intergers, write prime.\r<BR>\n" );
document.write( "\n" );
document.write( "The problem is:<BR>\n" );
document.write( "12q^2+34q-28 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220377 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12q^2+34q-28<BR>\n" );
document.write( "=2(6q^2+17q-14)<BR>\n" );
document.write( "6*-14=-84<BR>\n" );
document.write( "2 factors of -84 whose sum is 17 are 21 and -4<BR>\n" );
document.write( "2(6q^2+21q-4q-14)<BR>\n" );
document.write( "=2(3q(2q+7)-2(2q+7))<BR>\n" );
document.write( "=2(3q-2)(2q+7)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );