document.write( "Question 308199: log(x+2)=(logx)+ 2 \n" ); document.write( "

Algebra.Com's Answer #220374 by edjones(8007) $\"\"$ $\"About$

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log(x+2)=log(x)+ 2
\n" ); document.write( "log(x+2)-log(x)=2
\n" ); document.write( "10^(log(x+2))/10^log(x)= 10^2
\n" ); document.write( "(x+2)/x=100
\n" ); document.write( "x+2=100x
\n" ); document.write( "99x=2
\n" ); document.write( "x=2/99
\n" ); document.write( ".
\n" ); document.write( "Ed \n" ); document.write( "

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