document.write( "Question 308214: A freight train leaves a sterling traveling east at 40 miles per hour. Two hours later a passenger train also headed east, leaves Sterling on a parallel track at 60 miles per hour. How FAR are the trains from Sterling will the passenger train catches up to the freight train. \n" ); document.write( "
Algebra.Com's Answer #220368 by mananth(16946)\"\" \"About 
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A freight train leaves a sterling traveling east at 40 miles per hour. Two hours later a passenger train also headed east, leaves Sterling on a parallel track at 60 miles per hour. How FAR are the trains from Sterling will the passenger train catches up to the freight train.\r
\n" ); document.write( "\n" ); document.write( "Freight train rate = 40 mph
\n" ); document.write( "in 2 hours it will have traveled 80 miles.
\n" ); document.write( "Let this point be A\r
\n" ); document.write( "\n" ); document.write( "Let the point they meet be Y\r
\n" ); document.write( "\n" ); document.write( "Let the distance from A to B be x miles\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( "Passenger train rate = 60 mph
\n" ); document.write( "It has to travel x+80 miles to catch up with the freight train
\n" ); document.write( "The time taken by this train to go to B will be x+80/60
\n" ); document.write( ".
\n" ); document.write( "When the freight train is at point A passenger train is at the sterling.
\n" ); document.write( "The freight train travels x miles in the same time as the passenger train takes to travel x+80 miles
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\n" ); document.write( "\n" ); document.write( "time taken by freight train to travel x miles = x/40
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\n" ); document.write( "x/40 = x+80/60\r
\n" ); document.write( "\n" ); document.write( "60x=40(x+80)
\n" ); document.write( "60x=40x + 3200
\n" ); document.write( "20x= 3200
\n" ); document.write( "x=160 miles\r
\n" ); document.write( "\n" ); document.write( "The point they meet is x+80 miles
\n" ); document.write( "=160+80 miles = 240 miles\r
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