document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308109>Question 308109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do u I solve by subsitution method for <BR>\n" );
document.write( "x+4y=41<BR>\n" );
document.write( "4x+3y=60 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220359 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do u I solve by subsitution method for <BR>\n" );
document.write( "x+4y=41<BR>\n" );
document.write( "4x+3y=60<BR>\n" );
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document.write( "Solve the 1st eqn for x, since its coefficient is 1.<BR>\n" );
document.write( "x = 41-4y<BR>\n" );
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document.write( "Sub for x in the 2nd eqn<BR>\n" );
document.write( "4x + 3y = 60<BR>\n" );
document.write( "4(41-4y) + 3y = 60<BR>\n" );
document.write( "solve for y, then sub for y into either eqn and find x.<BR>\n" );
document.write( " </SPAN>\n" );
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