document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307918>Question 307918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> evaluate log (base1/5) 0.2 = x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220296 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your equation can be expressed (1/5)^x = 0.2 using rules of logs.\r<BR>\n" );
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document.write( "Take the natural log of both sides of the equation.\r<BR>\n" );
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document.write( "Let ln = natural log\r<BR>\n" );
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document.write( "ln(1/5)^x = ln(0.2)\r<BR>\n" );
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document.write( "(x/5)ln = ln(0.2)\r<BR>\n" );
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document.write( "x[ln(1/5)] = ln(0.2)\r<BR>\n" );
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document.write( "x = ln(0.2)/ln(1/5)\r<BR>\n" );
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document.write( "We now apply the calculator on the right side.\r<BR>\n" );
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document.write( "x = 1 </SPAN>\n" );
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