document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308033>Question 308033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the linear equation:<BR>\n" );
document.write( "- Find the missing coordinates of the given points. Show your work.<BR>\n" );
document.write( "- Plot those points and graph the linear equation.\r<BR>\n" );
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document.write( "3x + 4y = 12<BR>\n" );
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document.write( "(0, ), ( ,0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220275 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the first one, substitute x=0 into the equation and solve for y:\r<BR>\n" );
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document.write( "3x+4y=12<BR>\n" );
document.write( "3(0)+4y=12<BR>\n" );
document.write( "0+4y=12<BR>\n" );
document.write( "4y=12<BR>\n" );
document.write( "y=3\r<BR>\n" );
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document.write( "Next, substitute y=0 in and solve for x:\r<BR>\n" );
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document.write( "3x+4y=12<BR>\n" );
document.write( "3x+4(0)=12<BR>\n" );
document.write( "3x=12<BR>\n" );
document.write( "x=4\r<BR>\n" );
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document.write( "So (0,3) is one point, and another point is (4,0). </SPAN>\n" );
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