document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308032>Question 308032</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Given the linear equation:<BR>\n" );
document.write( "- Find the y-coordinates of the given points. Show your work.<BR>\n" );
document.write( "- Plot those points and graph the linear equation. <BR>\n" );
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document.write( "y = 1/3 x - 2<BR>\n" );
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document.write( "(0, ), (3, ), (-3, )<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220272 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just substitute the value into x, and solve for y.\r<BR>\n" );
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document.write( "i) x=0\r<BR>\n" );
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document.write( "y=1/3(0) -2<BR>\n" );
document.write( "y=0-2<BR>\n" );
document.write( "y=-2\r<BR>\n" );
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document.write( "(0,-2) is a point.\r<BR>\n" );
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document.write( "ii) x=3\r<BR>\n" );
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document.write( "y=(1/3)*3 - 2<BR>\n" );
document.write( "y=1-2<BR>\n" );
document.write( "y=-1\r<BR>\n" );
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document.write( "(3,-1) is another point.\r<BR>\n" );
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document.write( "iii) y=(1/3)*(-3) - 2<BR>\n" );
document.write( "y=-1-2<BR>\n" );
document.write( "y=-3\r<BR>\n" );
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document.write( "(-3,-3) is the last point. \r<BR>\n" );
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document.write( "Plot those three points on a graph, and then connect the dots to draw the line. If you want to see a picture of this, let me know. </SPAN>\n" );
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