document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308025>Question 308025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) A tractor applies a force of 1300N to the sled,which has mass of 11000kg.<BR>\n" );
document.write( "At that point the coefficient of friction increased to 0.80. what is the acceleration of the sled? and explain the significant of the sign.\r<BR>\n" );
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document.write( "Thanks.\r<BR>\n" );
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document.write( "James. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220267 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not really an algebra problem but here's how it's done.<BR>\n" );
document.write( "The sum of the forces equals mass multiplied by acceleration. <BR>\n" );
document.write( "I'm assuming the force applied by the tractor (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T ALIGN=MIDDLE  ALT=\"T\"   DISABLED_style= \"max-width:90%; height:auto;\" >) is perpendicular to the weight of the sled (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=mg ALIGN=MIDDLE  ALT=\"W=mg\"   DISABLED_style= \"max-width:90%; height:auto;\" >). The forces acting are the weight in the y direction (up-down) and an equal and opposite force from the floor so that y acceleration is zero. <BR>\n" );
document.write( "Friction acts in the direction to oppose movement (opposite the tractor pull force) and is equal to the product of the weight (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W ALIGN=MIDDLE  ALT=\"W\"   DISABLED_style= \"max-width:90%; height:auto;\" >) and friction coefficent (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=mu ALIGN=MIDDLE  ALT=\"mu\"   DISABLED_style= \"max-width:90%; height:auto;\" >).<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=F=ma=T-mu%2AW ALIGN=MIDDLE  ALT=\"F=ma=T-mu%2AW\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=%28T-mu%2Amg%29%2Fm=%281300-%280.8%2911000%289.8%29%29%2F11000 ALIGN=MIDDLE  ALT=\"a=%28T-mu%2Amg%29%2Fm=%281300-%280.8%2911000%289.8%29%29%2F11000\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Since the friction force is greater than the force applied by the tractor, the sled does not move. <BR>\n" );
document.write( "The tractor has to apply a force at least greater than <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=mu%2Amg=86240 ALIGN=MIDDLE  ALT=\"mu%2Amg=86240\"   DISABLED_style= \"max-width:90%; height:auto;\" > N to accelerate the sled. Any force less than that will not move the sled. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=0 ALIGN=MIDDLE  ALT=\"a=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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