document.write( "Question 308019: GIVE THE EXACT VALUE OF THE EXPRESSION:
\n" ); document.write( "INVERSE TANGENT OF THE SQAURE ROOT OF 3
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Algebra.Com's Answer #220260 by Fombitz(32388) $\"\"$ $\"About$

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You're looking for the angle whose sin= $\"sqrt%283%29%2F2\"$ and cos= $\"1%2F2\"$ or else sin= $\"-sqrt%283%29%2F2\"$ and cos= $\"-1%2F2\"$ .
\n" ); document.write( "Since tan=sin/cos, then tan= $\"sqrt%283%29\"$ .
\n" ); document.write( " $\"60\"$ degrees ( $\"pi%2F3\"$ ) or $\"240\"$ degreees ( $\"4pi%2F3\"$ ). \n" ); document.write( "

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