document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308017>Question 308017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7.	What fraction should be added to 3/8 and 5/12 to make the result 1\r<BR>\n" );
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document.write( "I'm not sure if I remember the right way to do this, but this is what I tried.\r<BR>\n" );
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document.write( "3/8 + 5/12 + a/b = 1<BR>\n" );
document.write( "3/8 = 9/24<BR>\n" );
document.write( "5/12 = 10/24<BR>\n" );
document.write( "19/24 + a/24 = 1<BR>\n" );
document.write( "19/24 + 5/24 = 24/24 = 1<BR>\n" );
document.write( "a/b = 5/24 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220257 by </B><A HREF=/tutors/aboutme.mpl?userid=JBarnum><B>JBarnum(2146)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JBarnum><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JBarnum><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> thats correct just had to find the common denominator and then add the 2 fractions then take that numerator and subtract it from the 1 made by the denominator.<BR>\n" );
document.write( "well done </SPAN>\n" );
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