document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308011>Question 308011</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the equation e^(2x)=20 for x .... <BR>\n" );
document.write( "a. x=10/e<BR>\n" );
document.write( "b. x=1n20/2<BR>\n" );
document.write( "c. x=1n10<BR>\n" );
document.write( "d. x=20-e/2 <BR>\n" );
document.write( "tthanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220255 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have to 'take the natural log' of both sides.\r<BR>\n" );
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document.write( "The natural log, LN, is the inverse function of the exponential e^\r<BR>\n" );
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document.write( "ln(e^2x) = ln(20)<BR>\n" );
document.write( "2x=ln20<BR>\n" );
document.write( "x=ln20/2\r<BR>\n" );
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document.write( "The answer is b. </SPAN>\n" );
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