document.write( "Question 308007: solve the equation e^(2x)=20 for x ....\r
\n" ); document.write( "\n" ); document.write( "a. x=10/e
\n" ); document.write( "b. x=1n20/2
\n" ); document.write( "c. x=1n10
\n" ); document.write( "d. x=20-e/2\r
\n" ); document.write( "\n" ); document.write( "tthanks!
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Algebra.Com's Answer #220248 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Start by taking the ln of each side of the equation to \"undo\" the \"e^\":
\n" ); document.write( "\"e%5E%282x%29=20\"
\n" ); document.write( "\"ln%28e%5E%282x%29%29=+ln+20\"
\n" ); document.write( "\"2x=+ln+20\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Divide by 2:
\n" ); document.write( "\"x=+ln20%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "You may want to see my website for help with LOGARITHMS! To find my website, just click on my tutor name \"Rapaljer\" anywhere in algebra.com. For written explanations, look for \"Basic, Intermediate, and College Algebra: One Step at a Time\", choose \"College Algebra\" and look for \"Chapter 4 Logarithms.\" See also the \"MATH IN LIVING COLOR\" pages that go with this explanation, where the exercises are solved IN COLOR!\r
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\n" ); document.write( "\n" ); document.write( "For VIDEO explanations, on my Homepage look for \"Rapalje Videos in Living Color\". Choose \"College Algebra\" and select the topics of \"Logarithms.\" These videos are from my own classroom a few years ago before I retired. I hope you find these helpful.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
\n" ); document.write( "Seminole State College of Florida
\n" ); document.write( "Altamonte Springs Campus
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