document.write( "Question 308002: what is the value of x in the equation ?\r
\n" ); document.write( "\n" ); document.write( "(square root 5x)-12=13\r
\n" ); document.write( "\n" ); document.write( "a. 1/125
\n" ); document.write( "b. 1/5
\n" ); document.write( "c. 25
\n" ); document.write( "d. 125\r
\n" ); document.write( "\n" ); document.write( "tthanks!
\n" ); document.write( "

Algebra.Com's Answer #220239 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%285x%29-12=13\" if \"Y=%28sqrt%285x%29%29\" then
\n" ); document.write( "\"Y-12=13\"
\n" ); document.write( "\"Y=25\"
\n" ); document.write( "\"sqrt%285x%29=25\" square both sides
\n" ); document.write( "\"5x=625\"divide by 5
\n" ); document.write( "\"x=125\"
\n" ); document.write( "Check
\n" ); document.write( "\"sqrt%285x%29-12=13\"
\n" ); document.write( "\"sqrt%285%28125%29%29-12=13\"
\n" ); document.write( "\"sqrt%28625%29-12=13\"
\n" ); document.write( "\"25-12=13\"
\n" ); document.write( "\"13=13\"
\n" ); document.write( "correct
\n" ); document.write( "
\n" );