document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307976>Question 307976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the width of a rectangle when the area is 480 ft. to the second power and the length is 24 ft. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220228 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of a rectangle = L*W\r<BR>\n" );
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document.write( "480=24*W, you must solve for W.\r<BR>\n" );
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document.write( "Divide both sides by 24:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=480%2F24=%2824W%29%2F24 ALIGN=MIDDLE  ALT=\"480%2F24=%2824W%29%2F24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20=W ALIGN=MIDDLE  ALT=\"20=W\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so width is 20 feet.\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired </SPAN>\n" );
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