document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307941>Question 307941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need to factor this by grouping and could use some help\r<BR>\n" );
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document.write( "(x - 2)(x + 1) = 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220220 by </B><A HREF=/tutors/aboutme.mpl?userid=TX911><B>TX911(36)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TX911><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TX911><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, multiply the two expressions together using the FOIL method: x^2+x-2x-2=4\r<BR>\n" );
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document.write( "Now set the equation equal to 0 by subtracting 4 from both sides: x^2+x-2x-6=0\r<BR>\n" );
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document.write( "Now we can do some simplifying: x^2-x-6=0<BR>\n" );
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document.write( "You can factor from here I think but here you go: (x-3)(x+2)\r<BR>\n" );
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document.write( "Hope this helps </SPAN>\n" );
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