document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307898>Question 307898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has a beaker of a 3% acid solution and a beaker of a 7% solution. He needs to make 75ml of a 4% acid solution.\r<BR>\n" );
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document.write( "Amount of solution (ml):  x 3% solution  + y 7% solution = ---------<BR>\n" );
document.write( "Amount of Acid (ml) : _______x  + ______y = 0.04(75)\r<BR>\n" );
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document.write( "Use the information in the table to write a system of linear equations.\r<BR>\n" );
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document.write( "Solve the system of equations to find how much he will use from each beaker. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220194 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has a beaker of a 3% acid solution and a beaker of a 7% solution. He needs to make 75ml of a 4% acid solution.\r<BR>\n" );
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document.write( "Amount of solution (ml):  x 3% solution  + y 7% solution = 75---------<BR>\n" );
document.write( "Amount of Acid (ml) : __0.03_____x  + __0.07____y = 0.04(75)\r<BR>\n" );
document.write( "\n" );
document.write( "Use the information in the table to write a system of linear equations.\r<BR>\n" );
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document.write( "Solve the system of equations to find how much he will use from each beaker.\r<BR>\n" );
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document.write( "x+y=75<BR>\n" );
document.write( "0.03x+0.07y=0.04*75<BR>\n" );
document.write( "Multiply the equation by 100\r<BR>\n" );
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document.write( "3x+7y= 300\r<BR>\n" );
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document.write( "3x+3y-3x-7y= 225-300<BR>\n" );
document.write( "-4y=-75<BR>\n" );
document.write( "y= 18.75 ml<BR>\n" );
document.write( "x=75-18.75<BR>\n" );
document.write( "x=56.25 ml\r<BR>\n" );
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document.write( " </SPAN>\n" );
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