document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307804>Question 307804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line passing through (-1, -3) and perpendicular to y = -2x + 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220179 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line passing through (-1, -3) and perpendicular to y = -2x + 3.\r<BR>\n" );
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document.write( "y= -2x +3\r<BR>\n" );
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document.write( "slope = -2 \r<BR>\n" );
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document.write( "slope of perpendicular line = +1/2\r<BR>\n" );
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document.write( "x1,y1 (-1, -3)\r<BR>\n" );
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document.write( "equation of line passing through a point x1 y1<BR>\n" );
document.write( "y-y1 = m(x-x1)\r<BR>\n" );
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document.write( "y-(-3)= 1/2 ( x-(-1))\r<BR>\n" );
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document.write( "y+3 = 1/2 (x+1)\r<BR>\n" );
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document.write( "2y+6 =x+1<BR>\n" );
document.write( "2y= x-5<BR>\n" );
document.write( "y= 1/2 x -5/2 is the perpendicular line  </SPAN>\n" );
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