document.write( "Question 307830: Ann walks 5 km/hr and betty walks 4 km/hr. If they start walking toward each other from a distance of 36 km, how many hours will it take for them to meet. \n" ); document.write( "
Algebra.Com's Answer #220146 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Ann walks 5 km/hr and betty walks 4 km/hr. If they start walking toward each other from a distance of 36 km, how many hours will it take for them to meet.\r \n" ); document.write( "\n" ); document.write( "let them meet at a distance x from Ann \n" ); document.write( "The distance from betty when they meet = 36-x \n" ); document.write( ". \n" ); document.write( "time taken to walk to the point of meeting by Ann = x/5 \n" ); document.write( "time taken by betty to walk to the point of meeting = 36-x/ 4\r \n" ); document.write( "\n" ); document.write( "These times are same \n" ); document.write( "x/5 = 36-x/4\r \n" ); document.write( "\n" ); document.write( "4x=5(36-x) \n" ); document.write( "4x=180-5x \n" ); document.write( "9x = 180 \n" ); document.write( "x= 20 miles.\r \n" ); document.write( "\n" ); document.write( "This is the distance traveled by Ann at 5 mph\r \n" ); document.write( "\n" ); document.write( "So they meet after 20 / 5 = 4 hours \n" ); document.write( " |