document.write( "Question 307830: Ann walks 5 km/hr and betty walks 4 km/hr. If they start walking toward each other from a distance of 36 km, how many hours will it take for them to meet. \n" ); document.write( "
Algebra.Com's Answer #220146 by mananth(16946)\"\" \"About 
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Ann walks 5 km/hr and betty walks 4 km/hr. If they start walking toward each other from a distance of 36 km, how many hours will it take for them to meet.\r
\n" ); document.write( "\n" ); document.write( "let them meet at a distance x from Ann
\n" ); document.write( "The distance from betty when they meet = 36-x
\n" ); document.write( ".
\n" ); document.write( "time taken to walk to the point of meeting by Ann = x/5
\n" ); document.write( "time taken by betty to walk to the point of meeting = 36-x/ 4\r
\n" ); document.write( "\n" ); document.write( "These times are same
\n" ); document.write( "x/5 = 36-x/4\r
\n" ); document.write( "\n" ); document.write( "4x=5(36-x)
\n" ); document.write( "4x=180-5x
\n" ); document.write( "9x = 180
\n" ); document.write( "x= 20 miles.\r
\n" ); document.write( "\n" ); document.write( "This is the distance traveled by Ann at 5 mph\r
\n" ); document.write( "\n" ); document.write( "So they meet after 20 / 5 = 4 hours
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