document.write( "Question 307737: 1. the dimensions of a rectangular flower garden were 8 m by 15 m. Each dimension was increased by the same amount. The garden then had an area of 198 m squared. Find the dimensions of the new garden.\r
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document.write( "2. a 7 x 10 in mirror was put in a frame and hung on the wall, the mirror and frame together cover an area of 130 in squared. How wide is the frame? \n" );
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Algebra.Com's Answer #220131 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 1. the dimensions of a rectangular flower garden were 8 m by 15 m. Each dimension was increased by the same amount. The garden then had an area of 198 m squared. Find the dimensions of the new garden.\r \n" ); document.write( "\n" ); document.write( "the dimensions of flower garden\r \n" ); document.write( "\n" ); document.write( "length = 15 m \n" ); document.write( "width = 8 m \n" ); document.write( ". \n" ); document.write( "increase each dimension by x m \n" ); document.write( "then the dimensions become \n" ); document.write( "x+15 \n" ); document.write( "x+8 \n" ); document.write( "The area of the garden after increase in dimension = 198 m^2\r \n" ); document.write( "\n" ); document.write( "Area = L * W\r \n" ); document.write( "\n" ); document.write( "(x+15)(x+8) =198 \n" ); document.write( "x(x+8)+15(x+8)=198 \n" ); document.write( "x^2+8x+15x+120=198 \n" ); document.write( "x^2+23x-78=0 .... (-198+120) \n" ); document.write( "x^2+26x-3x-78=0 \n" ); document.write( "x(x+26)-3(x+26)=0 \n" ); document.write( "(x+26)(x-3)=0 \n" ); document.write( "x=-26 OR x=3\r \n" ); document.write( "\n" ); document.write( "x=3 is practical and valid\r \n" ); document.write( "\n" ); document.write( "The new length = 15 +3=18 m \n" ); document.write( "The new width = 8 +3 = 11 \n" ); document.write( "- \n" ); document.write( "- \n" ); document.write( "2. a 7 x 10 in mirror was put in a frame and hung on the wall, the mirror and frame together cover an area of 130 in squared. How wide is the frame?\r \n" ); document.write( "\n" ); document.write( "length of mirror = 10 \n" ); document.write( "width of mirror = 7\r \n" ); document.write( "\n" ); document.write( "Let the width of the border be x \n" ); document.write( "Dimensions of frame\r \n" ); document.write( "\n" ); document.write( "New length = 10+2x \n" ); document.write( "New width = 7+2x\r \n" ); document.write( "\n" ); document.write( "(2x+7)(2x+10)=130 in squared\r \n" ); document.write( "\n" ); document.write( "2x(2x+10)+7(2x+10)=130 \n" ); document.write( "4x^2 +20x +14x +70=130 \n" ); document.write( "4x^2+34x - 60 =0 \n" ); document.write( "2x^2+17x-30=0 \n" ); document.write( "2x(x+10)-3(x+10)=0 \n" ); document.write( "(2x-3)(x+10)=0\r \n" ); document.write( "\n" ); document.write( "x=3/2 OR x= -20.. ( width of border = 3/2 . so increase in width is double)\r \n" ); document.write( "\n" ); document.write( "3 inches is the increase in width\r \n" ); document.write( "\n" ); document.write( "frame width = 7+3=10 inches\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |