document.write( "Question 307756: Solve log (5-2x) = 0 \n" ); document.write( "
Algebra.Com's Answer #220130 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"log%2810%2C5-2x%29=0\" which means that \"10%5E0=5-2x\"
\n" ); document.write( "\"1=5-2x\"
\n" ); document.write( "\"-4=-2x\"
\n" ); document.write( "\"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "I have additional explanation in both written and video format with examples solved in LIVING COLOR on my own website. Please go to \"www2.seminolestate.edu/rrapalje\". Look for the links on my Homepage \"Basic, Intermediate, and College Algebra: One Step at a Time\" and also \"MATH IN LIVING COLOR\", and look under \"College Algebra\" (Chapter 4). \r
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\n" ); document.write( "\n" ); document.write( "I also have a complete video from my own teaching in class before I retired a few years ago on Logarithms. To see the video, look for \"Rapalje Videos in Living Color\", and see College Algebra for the topic of Logarithms. \r
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\n" ); document.write( "\n" ); document.write( "I think you will find the explanations, both written and video, much easier to understand than traditional textbooks. Best of all, it's all FREE--even the VIDEO!!\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
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