document.write( "Question 307705: The speed of train A is 6 mph slower than the speed of train B. Train A travels 210 miles in the same time it takes train B to travel 240 miles. Find the speed of each. \n" ); document.write( "

Algebra.Com's Answer #220119 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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The speed of train A is 6 mph slower than the speed of train B.
\n" ); document.write( " Train A travels 210 miles in the same time it takes train B to travel 240 miles.
\n" ); document.write( " Find the speed of each.
\n" ); document.write( ":
\n" ); document.write( "Let s = speed of train A
\n" ); document.write( "then
\n" ); document.write( "(x+6) = speed of train B
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Train A time = train B time
\n" ); document.write( " $\"210%2Fs\"$ = $\"240%2F%28%28s%2B6%29%29\"$
\n" ); document.write( "Cross multiply
\n" ); document.write( "240s = 210(s+6)
\n" ); document.write( "240s = 210s + 1260
\n" ); document.write( "240s - 210s = 1260
\n" ); document.write( "30s = 1260
\n" ); document.write( "s = $\"1260%2F30\"$
\n" ); document.write( "s = 42 mph of train A
\n" ); document.write( "and obviously
\n" ); document.write( "42 + 6 = 48 mph is train B
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the time of each train
\n" ); document.write( "240/48 = 5 hrs
\n" ); document.write( "210/42 = 5 hrs, confirms our solutions \n" ); document.write( "

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