document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307747>Question 307747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are three consecutive integers. The sum of twice the second and third is 61. Find the three integers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220118 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the three consequitive numbers be x, x+1, x+2\r<BR>\n" );
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document.write( "2(x+1)+x+2 =61\r<BR>\n" );
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document.write( "2x+2 +x+2 =61<BR>\n" );
document.write( "3x+4=61\r<BR>\n" );
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document.write( "3x=57<BR>\n" );
document.write( "x=19\r<BR>\n" );
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document.write( "The numbers are 19,20,21 </SPAN>\n" );
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