document.write( "Question 307741: Solve the equation\r
\n" ); document.write( "\n" ); document.write( "3 log x = 1.5
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Algebra.Com's Answer #220113 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
First divide both sides by 3:\r
\n" ); document.write( "\n" ); document.write( "3 log x = 1.5\r
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\n" ); document.write( "\n" ); document.write( "log x = 1.5/3=15/30=1/2\r
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\n" ); document.write( "\n" ); document.write( "It might help to re-write this as
\n" ); document.write( "\"log%2810%2Cx%29=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "This means that \"10%5E%281%2F2%29=x\", so \"x=sqrt%2810%29\".\r
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\n" ); document.write( "\n" ); document.write( "I have quite a bit of explanation on LOGARITHMS with examples solved in LIVING COLOR on my own website. Please go to \"www2.seminolestate.edu/rrapalje\". Look for the links on my Homepage \"Basic, Intermediate, and College Algebra: One Step at a Time\" and also \"MATH IN LIVING COLOR\", and look under \"College Algebra\" (Chapter 4). The explanations on the MATH IN LIVING COLOR pages are complete with use of the GRAPHING CALCULATOR (TI84).\r
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\n" ); document.write( "\n" ); document.write( "I also have a complete explanation of Logarithms on video from my own teaching in class before I retired a few years ago. To see the videos, look for \"Rapalje Videos in Living Color\", and see College Algebra for the topic of Logarithms. \r
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\n" ); document.write( "\n" ); document.write( "I think you will find the explanations, both written and video, much easier to understand than traditional textbooks. And best of all, it's all FREE!!\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
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