document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307584>Question 307584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help\r<BR>\n" );
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document.write( "substitution method:\r<BR>\n" );
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document.write( "6x - y = 10<BR>\n" );
document.write( "     y = -3/4x - 1\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #220041 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=220041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> substitution method: <BR>\n" );
document.write( "6x - y = 10<BR>\n" );
document.write( "y = -3/4x - 1 <BR>\n" );
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document.write( "Sub for y into the 1st eqn<BR>\n" );
document.write( "substitution method: <BR>\n" );
document.write( "6x - y = 10<BR>\n" );
document.write( "6x - (-3x/4 - 1) = 10<BR>\n" );
document.write( "6x + 3x/4 + 1 = 10<BR>\n" );
document.write( "27x/4 = 9<BR>\n" );
document.write( "27x = 36<BR>\n" );
document.write( "x = 4/3<BR>\n" );
document.write( " </SPAN>\n" );
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